A Chapter in Python List Comprehension Abuse

Apparently Facebook held the qualification to this years Hackercup last weekend, I just came across some of the problems and decided to write a quick solution for one of them. And since Python has this awesome thing called list comprehensions, I managed to cram the solution into a single (ugly) line.
The task is basically this: Given a string, find how many times the string "HACKERCUP" can be formed from its letters without resusing any letters. (Full description here) Seems simple enough, lets see..
First, a little bit on list comprehensions. Usually, to define a list you do the following:


To fill a list, we could to this: But, it turns out there's an easier way - Python lets you create lists "implicitly", so to say. You can iterate over range(10) inside the list and create elements dynamically:

Looks interesting, and there's a lot you can do with this, because there are very few limitations on what you can put inside a list comprehension. You can even nest them to create matrices or do other things. The following line will flatten a list of lists:
For my solution to the problem, I actually read input inside a list comprehension, and then generate a list of that input to work with.

Here's the full code:

EXAMPLE INPUT

5
WELCOME TO FACEBOOK HACKERCUP
CUP WITH LABEL HACKERCUP BELONGS TO HACKER
QUICK CUTE BROWN FOX JUMPS OVER THE LAZY DOG
MOVE FAST BE BOLD
HACK THE HACKERCUP


EXAMPLE OUTPUT

Case #1: 1
Case #2: 2
Case #3: 1
Case #4: 0
Case #5: 1

It's a bit obfuscated, but should still be understandable. The print("\n".join(......)) part prints each element in the following list into a new line, so the output is in the required format. After that, we have the actual generation of our results.
In the last part - [raw_input() for x in range(int(raw_input))] - I read the input. range() takes the number of lines that follow, and then reads that many lines. This list is worked with by the outer list comprehension, which applies a formula to it to count how many times "HACKERCUP" can be formed out of each of the input strings' letters (tC means test case, n is the index of the test case we're on).
The actual formula is this:



We count how many times each letter (the variable c) in "HACKERCUP" occurs in the test case string, and divide by how often it appears in "HACKERCUP" in the first place (rounding down). We store each result in a list, and then take the minimum of that list, giving us our final result.

So, the code is pretty messy and arguably unpythonic, but it demonstrates pretty well how powerful list comprehensions are in Python. Wrap them up in a while(true) loop and you can even create whole mini-games in one line of code!